The common positive oxidation states for an element with atomic number 24, are

+1 and +3

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+1 to +6

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+1 and +3 to +6

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+2 to +6

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Solution

The correct option is D +2 to +6
$Z = 24$ for $C r$
Electronic configuration:
$[A r] 4 s^{1} 3 d^{5}$
The most common oxidation states for $C r$ are +2, +3, +4, +5 and +6.

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Similar questions

An element has $[A r] 3 d^{4}$ configuration in its +3 oxidation state. The atomic number of element is:

- 2

(A r) 3 d^{3}

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