Question

The common positive oxidation states for an element with atomic number 24, are

• A. +1 and +3
• B. +1 to +6
• C. +1 and +3 to +6
• D. +2 to +6

Answer 1

The correct option is D +2 to +6

$Z=24$ for $Cr$
Electronic configuration:
$\left[Ar\right]4s^{1}3d^5$
The most common oxidation states for $Cr$ are +2, +3, +4, +5 and +6.