The common root of the quadratic equations $x^{2} - 4$ = 0 and $x^{2} - 5 x + 6$ = 0 is .

-3

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Solution

The correct option is B 2
Using the identity : $a^{2} - b^{2}$ = $(a - b) (a + b$ ) ,
$x^{2} - 4$ = $(x - 2) (x + 2$ )
Hence, $x$ = 2, -2 are the roots the roots of $x^{2} - 4$ = 0.

Also, $x^{2} - 5 x + 6$ = $(x - 2) (x - 3$ )
Hence, $x$ = 2, 3 are the roots the roots of $x^{2} - 5 x + 6$ = 0.

Hence, the common root is 2.

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4 : 3

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