The common root of two equations (p2−√p+q+r2)x2+(√p+q−r2−1)x+(1−p2)=0 and m2x2−(r2+m2)x+r2=0 is
A
\N
No worries! We‘ve got your back. Try BYJU‘S free classes today!
B
1−p2r2
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
p2+r2−m2√p+q
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
none of these
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
Open in App
Solution
The correct option is D none of these (p2−√p+q+r2)x2+(√p+q−r2−1)x+(1−p2)=0 (p2+r2−√p+q)x2+(−p2−r2+√p+q+p2−1)x+(1−p2)=0 (p2+r2−√p+q)x[x−1]+(p2−1)(x−1)=0 (x−1)[(p2+r2−√p+q)x+(p2−1)]=0 m2x2−(r2+m2)x+r2=0 xm2(x−1)−r2(x−1)=0 (m2x−r2)(x−1)=0
Common root
x=1