The common root of $x^{2} - 3 x + 2$ and $x^{2} - 5 x + 6 = 0$

Open in App

Solution

$x^{2} - 3 x + 2 = 0 x^{2} - 2 x - x + 2 = 0 x (x - 2) - 1 (x - 2) = 0 (x - 1) (x - 2) = 0 x = 1, 2$ and $x^{2} - 5 x + 6 = 0 x^{2} - 2 x - 3 x + 6 = 0 x (x - 2) - 3 (x - 2) = 0 (x - 3) (x - 2) = 0 x = 2, 3$
So the common root is $2$

Suggest Corrections

Similar questions

x^{2} + x - 6 = 0, x^{2} + 3 x - 10 = 0

x^{2} - 5 x + 6 = 0

x^{2} - 8 x + 15 = 0

x^{2} + 4 x + q = 0

q

x^{2} - 4

x^{2} - 5 x + 6

x^{2} - 4 = 0 a n d x^{2} - 5 x + 6 = 0

x^{2} + 3 x + 2 = 0

x^{2} + k x + 6 = 0

Join BYJU'S Learning Program