The common tangents to the circle $x^{2} + y^{2} - 6 x = 0, x^{2} + y^{2} + 2 x = 0$ form

Right angled triangle

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Isosceles triangle

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Equilateral triangle

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Isosceles right angled triangle

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Solution

The correct option is C Equilateral triangle

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Similar questions

x^{2} + y^{2} - 6 x = 0

x^{2} + y^{2} + 2 x = 0

x^{2} + y^{2} + 2 x = 0

x^{2} + y^{2} - 6 x = 0

x^{2} + y^{2} - 6 x = 0 a n d x^{2} + y^{2} + 2 x = 0

y^{2} = 4 x

x^{2} + y^{2} + 2 x = 0

x^{2} + y^{2} - 6 x = 0

x^{2} + y^{2} + 2 x = 0

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