The common tangents to the circles x2+y2−6x=0 and x2+y2+2x=0 is/are
A
x=0
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B
√3y=x+3
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C
√3y+x+3=0
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D
y=0
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Solution
The correct option is C√3y+x+3=0 Using the section formulae we get P≡(−3,0)
Now angle made by the tangents to the x−axis is sinθ=12⇒θ=30°
So the equation of the tangents will be √3y=±(x+3) and x=0