The complement of 40- is-

Let the complement be nbsp;x^∘. Sum of nbsp;two complementary nbsp; nbsp;angles = 90^∘. Hence, 40^∘ + x^∘ = 90^∘ ⇒ x = 50^∘. So, the complement of n ...

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Standard VI

Mathematics

Complementary Angles

The complemen...

Question

The complement of $40^{\circ}$ is:

$45^{\circ}$

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$50^{\circ}$

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$140^{\circ}$

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$80^{\circ}$

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Solution

The correct option is B
$50^{\circ}$

Let the complement be $x^{\circ}$ .
Sum of two complementary angles = $90^{\circ}$ .
Hence,
$40^{\circ} + x^{\circ}$ = $90^{\circ}$
$\Rightarrow x = 50^{\circ}$ .
So, the complement of $40^{\circ} i s 50^{\circ}$ .

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The complement of 40∘ is:

The correct option is B 50∘ Let the complement be x∘. Sum of two complementary angles = 90∘. Hence, 40∘+x∘ = 90∘ ⇒x=50∘. So, the complement of 40∘ is 50∘.

The complement of $40^{\circ}$ is:

The correct option is B
$50^{\circ}$

Let the complement be $x^{\circ}$ .
Sum of two complementary angles = $90^{\circ}$ .
Hence,
$40^{\circ} + x^{\circ}$ = $90^{\circ}$
$\Rightarrow x = 50^{\circ}$ .
So, the complement of $40^{\circ} i s 50^{\circ}$ .