The complement of 72°40' is
(a) 107°20'
(b) 27°20'
(c) 17°20'
(d) 12°40'

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Solution

(c) 17°20'

We know that $90 ° = 89 ° 60'$
The complement of $72 ° 40' = (89 ° 60' - 72 ° 40')$
$= 17 ° 20'$

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What should be added to $\frac{7}{12} to get \frac{- 4}{15}$ ?

(a) $\frac{17}{20}$

(b) $\frac{- 17}{20}$

(d) $\frac{- 7}{20}$

The complement of 72 degree 40 seconds

| 5 x + 20 | = 80

Find:

(a) 35 − (20) (b) 72 − (90)

(e) 23 − (− 12) (f) (− 32) − (− 40)

\frac{1}{2} + \frac{1}{6} + \frac{1}{12} + \frac{1}{20} + . . . + \frac{1}{420}

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