Question

The complement of an angle exceeds the angle by ${60}^{\circ }$. Then the angle is equal to

• A. ${25}^{\circ }$
• B. ${30}^{\circ }$
• C. ${15}^{\circ }$
• D. ${35}^{\circ }$

Answer 1

The correct option is C ${15}^{\circ }$

Let angle $=x$

complement $=90-x$

$90-x=x+60$ (Given)

$2x=30$

$x={15}^{\circ }$