The complete graph of the function $f$ is shown in the $x y$ plane above. Which of the following are equal to 1?
I. $f (- 4)$
II. $f (\frac{3}{2})$
III. $f (3)$

III only

No worries! We‘ve got your back. Try BYJU‘S free classes today!

I and III only

No worries! We‘ve got your back. Try BYJU‘S free classes today!

II and III only

No worries! We‘ve got your back. Try BYJU‘S free classes today!

I, II, and III

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

Open in App

Solution

The correct option is D I, II, and III
It can be seen from the graph that f is constant from $x = 1$ to $x = 3$ at $y = 1.$

Clearly at all given points value of f is $1$ .

Suggest Corrections

Similar questions

[C r (N O_{2})_{3} (N H_{3})_{3}]

K_{3} [F e (C_{2} O_{4})_{3}]

[C o C l_{2} (e n)_{2}]^{+}

[C o B r C l (o x)_{2}]^{3 -}

f : [- 3, 7) \to R

f (x) = ⎧ ⎪ ⎨ ⎪ ⎩ \begin{matrix} 4 x^{2} - 1; & - 3 \leq x < 2 3 x - 2; & 2 \leq x \leq 4 2 x - 3; & 4 < x < 7 \end{matrix}

f (5) + f (6)

f (1) - f (3)

f (- 2) - f (- 4)

\frac{f (3) + f (1)}{2 f (6) - f (1)}

What will be (i), (ii) and (iii) if the following reaction is balanced?

$i) F e C l_{3} + (i i) M g O \to F e_{2} O_{3} + (i i i) M g C l_{2}$

If L and H divorced, then H could marry

I) D only

II) F

III) D or G

N a_{2} S_{4} O_{6} I, F e_{3} O_{4} I I, N_{3} H I I I

Join BYJU'S Learning Program