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Question

The complete solution of the equation 7cos2x+sinxcosx3=0 is given by

A
nπ+π2,(nI)
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B
nππ4,(nI)
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C
nπtan143,(nI)
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D
nπ+tan143,(nI)
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Solution

The correct option is C nππ4,(nI)
7cos2x+sinxcosx3=01+7cos2x+sin2x=0
Substituting
y=tanxsin2x=2y1+y2,cos2x=1y21+y2
2(3y2y4)y2+1=03y2y4=0(y+1)(3y4)=0
y=1 or 3y4=0
tanx=1 or tanx=43
x=πnπ4 or x=πm+tan143

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