CameraIcon
CameraIcon
SearchIcon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

The complete solution of the equation 7cos2x+sinxcosx3=0 is given by

A
nπ+π2,(nI)
No worries! We‘ve got your back. Try BYJU‘S free classes today!
B
nππ4,(nI)
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
C
nπtan143,(nI)
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
nπ+tan143,(nI)
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
Open in App
Solution

The correct option is C nππ4,(nI)
7cos2x+sinxcosx3=01+7cos2x+sin2x=0
Substituting
y=tanxsin2x=2y1+y2,cos2x=1y21+y2
2(3y2y4)y2+1=03y2y4=0(y+1)(3y4)=0
y=1 or 3y4=0
tanx=1 or tanx=43
x=πnπ4 or x=πm+tan143

flag
Suggest Corrections
thumbs-up
0
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
General Solutions
MATHEMATICS
Watch in App
Join BYJU'S Learning Program
CrossIcon