The complex ion ${[C o {(N H_{3})}_{6}]}_{6}^{+ 2}$ is readily oxidized to ${[C o {(N H_{3})}_{6}]}_{6}^{+ 3} .$

True

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False

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Solution

The correct option is A True
The complex ion $[C o (N H_{3})_{6}]^{+ 2}$ is readily oxidized to $[C o (N H_{3})_{6}]^{+ 3}$ . This is because although the ligands are the same in both the coordination complexes. But ln $[C o (N H_{3})_{o}]^{+ 2}$ the $C o^{+ 2}$ has $3 d^{7} 4 s^{o}$ and ln $[C o (N H_{3})_{6}]^{+ 3}$ the $C o^{+ 3}$ has $3 d^{6} 4 s^{o}$ . So, gain of electron i.e. oxidation takes place readily from $[C o (N H_{3})_{6}]^{2 +}$ to $[C o (N H_{3})_{6}]^{+ 3}$ .

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Similar questions

Q. Assertion :Complex ion

[C o (N H_{3})_{6}]^{2 +}

is readily oxidized to

[C o (N H_{3})_{6}]^{3 +}

Reason: Unpaired electron in complex ion

[C o (N H_{3})_{6}]^{2 +}

is present in 4p orbital.

The colour of the coordination compounds depends on the crystal field splitting. What will be the correct order of absorption of wavelength of light in the visible region, for the complexes, $[C o (N H_{3})_{6}]^{3 +}, [C o (C N)_{6}]^{3 -}, [C o (H_{2} O)_{6}]^{3 +}$
$[C o (N H_{3})_{6}]^{3 +}, [C o (C N)_{6}]^{3 -}, [C o (H_{2} O)_{6}]^{3 +}$
(a) $[C o (C N)_{6}]^{3 -} > [C o (N H_{3})_{6}]^{3 +} > [C o (H_{2} O)_{6}]^{3 +}$
(b) $[C o (N H_{3})_{6}]^{3 +} > [C o (H_{2} O)_{6}]^{3 +} > [C o (N H_{3})_{6}]^{3 +}$
(c) $[C o (H_{2} O)_{6}]^{3 +} > [C o (N H_{3})_{6}]^{3 +} > [C o (C N)_{6}]^{3 -}$
(d) $[C o (C N)_{6}]^{3 -} > [C o (N H_{3})_{6}]^{3 +} > [C o (H_{2} O)_{6}]^{3 +}$

Q. The oxidation state of cobalt in the complex compound

[C o (N H_{3})_{6}] C l_{3}

Indicate the complex ion which shows geometrical isomerism.
(a) $[C r (H_{2} O)_{4} C l_{2}]^{+}$
(b) $[P t (N H_{3})_{3} C l]$
(c) $[C o (N H_{3})_{6}]^{3 +}$
(d) $[C o (C N)_{5} (N C)]^{3 -}$

Q. The EAN of the complex

[C o (N H_{3})_{6}]^{3 +}

is:

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The complex ion [Co(NH3)6]+2 is readily oxidized to [Co(NH3)6]+3.

The complex ion ${[C o {(N H_{3})}_{6}]}_{6}^{+ 2}$ is readily oxidized to ${[C o {(N H_{3})}_{6}]}_{6}^{+ 3} .$