The complex ion trans-dichlorobis(ethylenediamine) rhodium (III) is optically active.

True

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False

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Solution

The correct option is B False
The given statement is False.
The complex ion trans-dichlorobis(ethylenediamine) rhodium (III) is optically inactive meso compound as it has plane of symmetry. The cis isomer is optically active and exists in the form of a pair of enantiomers (d and l form).

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Similar questions

Q. The complex ion;

[P t (N H_{3}) (N H_{2} O H) (N O_{2}) (P y)]^{+}

has been found to be optically active,then the probable geometry of the complex is:

The necessary and sufficient condition to exhibit optical activity, the configuration of the given complex should be assymmetric.

The complex which does not exhibit cis

-

trans isomerism but optically active

Q. Consider the following complexes.
(i)

[C r (E D T A)]^{-}

(ii)

[R u (e n)_{3}]^{2 +}

(iii)

[P t (g l y)_{2} C l_{2}]^{- 2}

(iv)

C i s - [C r (C l)_{2} (o x)_{2}]^{3 -}

(v) trans -

[P t (e n) (N H_{3})_{2} (p y)_{2}]^{4 +}

Then find out the value of expression

| p + q |^{2}

p = total number of optically active complexes

q = total number of optically inactive complexes

Q. Which of the following complex ion is optically active?

The following complexex are given:
(1) $t r a n s - [C o (N H_{3})_{4} C l_{2}]^{+}$
(2) $c i s - [C o (N H_{3})_{2} (e n)_{2}]^{3 +}$
(3) $t r a n s - [C o (N H_{3})_{2} (e n)_{2}]^{3 +}$
(4) $[N i C l_{4}]^{2 -}$
(5) $[T i F_{6}]^{2 -}$
(6) $[C o F_{6}]^{3 -}$
Choose the correct code:

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The complex ion trans-dichlorobis(ethylenediamine) rhodium (III) is optically active.

The correct option is B FalseThe given statement is False.The complex ion trans-dichlorobis(ethylenediamine) rhodium (III) is optically inactive meso compound as it has plane of symmetry. The cis isomer is optically active and exists in the form of a pair of enantiomers (d and l form).

The correct option is B False
The given statement is False.
The complex ion trans-dichlorobis(ethylenediamine) rhodium (III) is optically inactive meso compound as it has plane of symmetry. The cis isomer is optically active and exists in the form of a pair of enantiomers (d and l form).