wiz-icon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

The complex number z=x+iy which satisfies the equation ∣∣∣z−7iz+7i∣∣∣=1 lies on

A
x-axis
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
B
y-axis
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
on a circle
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
the line y=7
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution

The correct option is A x-axis
Simplifying, we get
|z7i|=|z+7i|
Let z=x+iy
Hence,
(x)2+(y7)2=x2+(y+7)2
(y+7)2(y7)2=0
28y=0
y=0
Therefore, z lies on x axis. Hence z is purely real.

flag
Suggest Corrections
thumbs-up
0
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
MATHEMATICS
Watch in App
Join BYJU'S Learning Program
CrossIcon