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Question

The complex number z=x+iy which satisfies the equation ∣∣∣z−7iz+7i∣∣∣=1 lies on

A
x-axis
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B
y-axis
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C
on a circle
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D
the line y=7
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Solution

The correct option is A x-axis
Simplifying, we get
|z7i|=|z+7i|
Let z=x+iy
Hence,
(x)2+(y7)2=x2+(y+7)2
(y+7)2(y7)2=0
28y=0
y=0
Therefore, z lies on x axis. Hence z is purely real.

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