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Question

The complex number z having least positive argument which satisfies the condition |z25i|15

A
25i
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B
12+5i
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C
16+12i
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D
12+16i
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Solution

The correct options are
A 25i
D 12+16i
Given that z has least positive argument
arg(z)0
tan1(|y/x|)0
also |z25i|15
i.e x2+(y25)2225
This is the equation of all points lying on or inside the circle with center(0,25i) and radius =15
as shown in diagram, the least +ve argument will be of the point on the circle whose tangent passes through origin
arg(z)=θ=90sin1(1525)
=9053
=37
|z|=x2+y2
|z|=252152
=400
=20
ans=12+16i

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