The correct options are
A 25i
D 12+16i
Given that z has least positive argument
∴arg(z)≥0
∴tan−1(|y/x|)≥0
also |z−25i|≤15
i.e x2+(y−25)2≤225
This is the equation of all points lying on or inside the circle with center(0,25i) and radius =15
∴ as shown in diagram, the least +ve argument will be of the point on the circle whose tangent passes through origin
arg(z)=θ=90−sin−1(1525)
=90−53∘
=37∘
|z|=√x2+y2
⇒|z|=√252−152
=√400
=20
∴ans=12+16i