The complex number z in the second quadrant which satisfies the equation z3=8i is
A
i−2√3
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B
2i−√3
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C
i−√3
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D
2i−3√3
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Solution
The correct option is Ci−√3 z3=8i ⇒z3=−8i3 ⇒(z−2i)3=1 ⇒z−2i=1orωorω2 ⇒z=−2ior−2iωor−2iω2 ⇒z=−2ior−2i(−1+√3i2)or−2i(−1−√3i2)
Hence, z=−2iori+√3ori−√3 out of which i−√3 lies in second quadrant.