The complex number z=x+iy which satisfies the equation ∣∣∣z−3iz+3i∣∣∣=1lies on
A
the X-axis
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B
the straight line y=3
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C
a circle passing through origin
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D
None of the above
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Solution
The correct option is A the X-axis ∣∣z−3iz+3i∣∣=1 ⇒|z−3i||z+3i|=1 ⇒|z−3i|=|z+3i| ⇒|x+iy−3i|=|x+iy+3i| squaringbothsides |x+iy−3i|2=|x+iy+3i|2 ⇒|x+i(y−3)|2=|x+i(y+3)|2 ⇒x2+(y−3)2=x2+(y+3)2 ⇒x2+y2+9−6y=x2+y2+9+6y ⇒12y=0 ⇒y=0 x−axis