Question

The complexes $\left[Co\right(N{H}_3{)}_{5}Br]S{O}_4$ and $\left[Co\right(N{H}_3{)}_{5}S{O}_4]Br$ can be distinguished by:

• A. $BaC{l}_2$
• B. $AgN{O}_3$
• C. $PbC{l}_2$
• D. $CuS{O}_4$

Answer 1

Answer: (A), (B)

The correct options are
A $AgN{O}_3$
B $BaC{l}_2$

The complexes $\left[Co\right(N{H}_3{)}_{5}Br]S{O}_4$ and $\left[Co\right(N{H}_3{)}_{5}S{O}_4]Br$ can be distinguished by $BaC{l}_2$ and $AgN{O}_3$.

$\left[Co\right(N{H}_3{)}_{5}Br]S{O}_4$ furnishes sulphate ions in the solution which react with $BaC{l}_2$ to form white ppt of $BaS{O}_4$.

$\left[Co\right(N{H}_3{)}_{5}S{O}_4]Br$ furnishes bromide ions in the solution which reacts with $AgN{O}_3$ to form yellow ppt of $AgBr$.

$\left[Co\right(N{H}_3{)}_{5}Br]S{O}_4+BaC{l}_2\to [Co\left(N{H}_3{)}_{5}Br\right]C{l}_2+\underset{White}{BaS{O}_4}\downarrow$

$\left[Co\right(N{H}_3{)}_{5}S{O}_4]Br+AgN{O}_3\to [Co\left(N{H}_3{)}_{5}S{O}_4\right]N{O}_3+\underset{yellow}{AgBr\downarrow }$

Optins A and B correct.