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Question

The condition f(x)=x3+px2+qx+r,xR to have no extreme value, is


A

p2<3q

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B

2p2<q

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C

p2<14q

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D

p2>3q

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Solution

The correct option is A

p2<3q


Explanation for the correct option:

Finding the condition:

Given Equation f(x)=x3+px2+qx+r,xR

To have no extreme value, f'(x)0

f'(x)=3x2+2px+q0

And also, the discriminant should be less than 0,

Hence, D<0

4p24×3×q<04p212q<0p2<3q

Hence, option (A) is the correct answer.


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