The component vector of b Perpendicular to a isA- a - b - a - a -2B- a - b - a - b -2C- b - a - b -a-2D- b - a - b - b -2

The correct option is A Comp. vector of b̅ for to a̅ = b̅ ( b̅×a̅)a̅/ | a̅ |^2 =(a̅. a̅)b̅ (a̅.b̅)a̅/ | a̅ |^2=a̅× (b̅×a̅)/ | a̅ |^2 ...

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Multiplication of a Vector by a Scalar

The component...

Question

The component vector of $¯ b$ Perpendicular to $¯ a$ is

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Similar questions

\vec{b}

\vec{a}

(\vec{b} . \vec{c}) \vec{a}

\frac{\vec{a} \times (\vec{b} \times \vec{a})}{{|\vec{a}|}^{2}}

\vec{a} \times (\vec{b} \times \vec{a})

(\to A + \to B)

\to B

\to A + 2 \to B

\to A

[\vec{a} \vec{b} \vec{a} \times \vec{b}] + {(\vec{a} . \vec{b})}^{2} =

{|\vec{a}|}^{2} {|\vec{b}|}^{2}

{|\vec{a} + \vec{b}|}^{2}

{|\vec{a}|}^{2} + {|\vec{b}|}^{2}

2 {|\vec{a}|}^{2} {|\vec{b}|}^{2}

If a, b $ϵ$ $R^{+}$ [ $R^{+}$ denote real positive numbers] then $\frac{a b}{a + b}$ is

{(\vec{a} \times \vec{b})}^{2}

{|\vec{a}|}^{2} + {|\vec{b}|}^{2} - {(\vec{a} \cdot \vec{b})}^{2}

{|\vec{a}|}^{2} {|\vec{b}|}^{2} - {(\vec{a} \cdot \vec{b})}^{2}

{|\vec{a}|}^{2} + {|\vec{b}|}^{2} - 2 (\vec{a} \cdot \vec{b})

{|\vec{a}|}^{2} + {|\vec{b}|}^{2} - \vec{a} \cdot \vec{b}

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