The compound $2 -$ methy $- 2 -$ butene on reaction with $N a I O_{4}$ in the presence of $K M n O_{4}$ gives :

C H_{3} C O O H

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C H_{3} C O C H_{3} + C H_{3} C O O H

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C H_{3} C O C H_{3} + C H_{3} C H O

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C H_{3} C H O + C O_{2}

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Solution

The correct option is B $C H_{3} C O C H_{3} + C H_{3} C O O H$
When 2-methy-2-butene is reacted with $N a I O_{4}$ in presence of $K M n O_{4}$ , the carbon carbon double bond breaks. The carbon atoms attached by carbon carbon double bond are oxidized to form acetone and acetic acid.

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Similar questions

The compound $C H_{3} | C H_{3} - C = C H - C H_{3}$ on reaction with $N a I O_{4}$ in the presence of $K M n O_{4}$ gives

C H_{3} C = C C H_{2} C H_{3} \frac{K M n O_{4} . K O H}{373 - 383 K}

(C H_{3})_{2} C = C H C H_{3}

K M n O_{4}

C H_{3} O H, C H_{3} C O O H, C H_{3} C H O, C H_{3} C O C H_{3}

N a I O_{4}

K M n O_{4}

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