Question

The compound A in the following reaction is:

• A. ${\mathrm{C}}_6{\mathrm{H}}_5-{\mathrm{CH}}_2-\stackrel{\stackrel{\mathrm{O}}{\mathrm{II}}}{\mathrm{C}}-{\mathrm{CH}}_3$
• B. ${\mathrm{C}}_6{\mathrm{H}}_5-\stackrel{\stackrel{\mathrm{O}}{\mathrm{II}}}{\mathrm{C}}-{\mathrm{CH}}_3$
• C. ${\mathrm{C}}_6{\mathrm{H}}_5-\stackrel{\mathrm{O}}{\stackrel{\mathrm{II}}{\mathrm{C}}}-\underset{\underset{{\mathrm{CH}}_3}{\mathrm{I}}}{\stackrel{\stackrel{{\mathrm{CH}}_3}{\mathrm{I}}}{\mathrm{CH}}}$
• D. ${\mathrm{C}}_6{\mathrm{H}}_5-\stackrel{\stackrel{\mathrm{O}}{\mathrm{II}}}{\mathrm{C}}-{\mathrm{CH}}_2{\mathrm{CH}}_3$

Answer 1

The correct option is A

${\mathrm{C}}_6{\mathrm{H}}_5-{\mathrm{CH}}_2-\stackrel{\stackrel{\mathrm{O}}{\mathrm{II}}}{\mathrm{C}}-{\mathrm{CH}}_3$

The explanation for the correct option:

Option (A): ${\mathrm{C}}_6{\mathrm{H}}_5-{\mathrm{CH}}_2-\stackrel{\stackrel{\mathrm{O}}{\mathrm{II}}}{\mathrm{C}}-{\mathrm{CH}}_3$

1. When ketone($1-$phenyl prop$-2-$one) reacts with Grignard reagent alcohol is formed which on further treatment with concentrated sulfuric acid forms alkene ($1-$phenyl$-2-$methyl prop$-2-$ene).
2. This alkene ($1-$phenyl$-2-$methyl prop$-2-$ene) undergoes ozonolysis and breaks a double bond to form two ketone products.
3. $4-$penten$-2-$one$-4-$methyl is formed when Prop$-2-$one the ketone reacts in the presence of ${\mathrm{BaOH}}_2$
4. Ketone reacts with concentrated potassium hydroxide to yield benzyl alcohol along with potassium salt of benzoic acid.

Therefore, The compound A is ${\mathrm{C}}_6{\mathrm{H}}_5-{\mathrm{CH}}_2-\stackrel{\stackrel{\mathrm{O}}{\mathrm{II}}}{\mathrm{C}}-{\mathrm{CH}}_3$