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Hydrogen Peroxide

The compound ...

Question

The compound A on treating with $N a$ gives $B$ , and with $P C l_{5}$ gives $C$ . $B$ and $C$ react together to give diethyl ether. $A, B$ and $C$ are in the order

A

C_{2} H_{5} O H, C_{2} H_{5} O N a, C_{2} H_{5} C l

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B

C_{2} H_{5} C l, C_{2} H_{6}, C_{2} H_{5} O H

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C

C_{2} H_{5} O H, C_{2} H_{5} C l, C_{2} H_{5} O N a

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D

C_{2} H_{5} O H, C_{2} H_{6}, C_{2} H_{5} C l

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Solution

The correct option is A $C_{2} H_{5} O H, C_{2} H_{5} O N a, C_{2} H_{5} C l$
The compound A is ethanol $C_{2} H_{5} O H$ . The compound A on treatment with Na gives sodium ethoxide $(C_{2} H_{5} O N a)$ which is compound B.
$C_{2} H_{5} O H N a - - \to - H_{2} C_{2} H_{5} O N a$
The compound A on treatment with $P C l_{5}$ gives ethyl chloride $(C_{2} H_{5} C l)$ which is compound C.
$C_{2} H_{5} O H P C l_{5} - -- \to C_{2} H_{5} C l + H C l + P O C l_{3}$
B and C react together to give diethyl ether.
$C_{2} H_{5} O N a + C_{2} H_{5} C l \to C_{2} H_{5} O C_{2} H_{5} + N a C l$
This reaction is known as Williamson Synthesis.

A, B and C are in the order $C_{2} H_{5} O H, C_{2} H_{5} O N a, C_{2} H_{5} C l$

Hence, option (a) is correct.

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Hydrogen Peroxide

Standard XII Chemistry

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