The compound $B$ formed in the following sequences of reactions is:
$C H_{3} C H_{2} C H_{2} O H P C l_{3} \to A A l c . K O H \to B$ .

propyne

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propene

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propanol

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propane

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Solution

The correct option is C propene
$C H_{3} C H_{2} C H_{2} O H P C l_{3} \to C H_{3} C H_{2} C H_{2} C l p r o p y l c h l o r i d e a l c . K O H \to C H_{3} C H = C H_{2} p r o p e n e$
In the first step the propyl alcohol undergo substitution reaction to form propyl chloride as a proudct which in presence of alc. KOH undergoes elimination reaction to form propene as a product.

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Similar questions

The compound (B) formed in the following sequence of reactions

$C H_{3} C H_{2} C H_{2} O H P C l_{5} - -- \to (A) a l c . K O H - ---- \to (B)$

C H_{3} - C H_{2} - C H_{2} - C l (a) p r o p y l c h l o r i d e) A l c . K O H - ----- \to C H_{3} - C H = C H_{2} (P r o p e n e b)

C H_{3} - C H_{2} - C H_{2} - C l (a) p r o p y l c h l o r i d e) A l c . K O H - ----- \to C H_{3} - C H = C H_{2} (P r o p e n e b)

C H_{3} C H_{2} C H_{2} O H P C l_{5} - -- \to A a l c o h o l i c - ---- \to K O H

C H_{3} - C H_{2} - O H P B r_{3} - -- \to (A) a l c . K O H - ----- \to (B) B r_{2} / C C l_{4} - ----- \to (C)

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