You visited us 3 times! Enjoying our articles? Unlock Full Access!

Byju's Answer

Standard XII

Chemistry

Diastereomers

The compound ...

Question

The compound $C_{5} H_{13} N$ is optically active and reacts with HONO to give $C_{5} H_{11} O H$ . The compound is:

N-methylbutanamine

No worries! We‘ve got your back. Try BYJU‘S free classes today!

2-aminopentane

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

1-aminopentane

No worries! We‘ve got your back. Try BYJU‘S free classes today!

N, N-dimethylpropanamine

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is B 2-aminopentane
Primary amine reacts with $H O N O$ to form alcohol.

Thus, $C_{5} H_{13} N$ is a primary amine.

$C_{5} H_{13} N$ is optically active compound.

Hence, $C_{5} H_{13} N$ is 2-aminopentane.

Option B is correct.

Suggest Corrections

Similar questions

The compound C₅H₁₃N is optically active and reacts with HONO to give C₅H₁₁OH. The compound is

Q. An organic compound A has molecular formula

C_{8} H_{12}

and is optically active It reacts with

H_{2} / P t

to give

B (C_{8} H_{18})

which is optically inactive Careful hydrogenation of A with

P d / B a S O_{4}

gives

C (C_{8} H_{14})

which is still optically active Compound A reacts with Na in liquid ammonia to give Diastereomer of C, but it is optically inactive Deduce structures of A to D.

Q. An optically active compound 'X' has molecular formula

C_{4} H_{8} O_{3}

. It evolves

C O_{2}

with aq.

N a H C O_{3}

X

reacts with

L i A l H_{4}

to give an achiral compound.

X

is :

Q. An organic compound

X

having molecular formula

C_{4} H_{11} N

reacts with

p -

toluene sulphonyl chloride to form a compound

Y

that is soluble in aqueous

K O H

. Compound

X

is optically active and reacts with acetyl chloride to form compound

Z

. Identify the compound

Z

Q. An optically active compound '

X

' has molecular formula

C_{4} H_{8} O_{3}

. It evolves

C O_{2}

with aqueous

N a H C O_{3}

. '

X

' reacts with

L i A l H_{4}

to give an achiral compound. '

X

' is :

Join BYJU'S Learning Program

The compound C5H13N is optically active and reacts with HONO to give C5H11OH. The compound is:

The correct option is B 2-aminopentanePrimary amine reacts with HONO to form alcohol. Thus, C5H13N is a primary amine.C5H13N is optically active compound.Hence, C5H13N is 2-aminopentane.Option B is correct.

The compound $C_{5} H_{13} N$ is optically active and reacts with HONO to give $C_{5} H_{11} O H$ . The compound is:

The correct option is B 2-aminopentane
Primary amine reacts with $H O N O$ to form alcohol.

Thus, $C_{5} H_{13} N$ is a primary amine.

$C_{5} H_{13} N$ is optically active compound.

Hence, $C_{5} H_{13} N$ is 2-aminopentane.

Option B is correct.