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Standard XII

Chemistry

Diastereomers

The compound ...

Question

The compound $C_{5} H_{13} N$ is optically active and reacts with HONO to give $C_{5} H_{11} O H$ . The compound is:

N-methylbutanamine

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2-aminopentane

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1-aminopentane

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N, N-dimethylpropanamine

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Solution

The correct option is B 2-aminopentane
Primary amine reacts with $H O N O$ to form alcohol.

Thus, $C_{5} H_{13} N$ is a primary amine.

$C_{5} H_{13} N$ is optically active compound.

Hence, $C_{5} H_{13} N$ is 2-aminopentane.

Option B is correct.

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The compound C5H13N is optically active and reacts with HONO to give C5H11OH. The compound is:

The correct option is B 2-aminopentanePrimary amine reacts with HONO to form alcohol. Thus, C5H13N is a primary amine.C5H13N is optically active compound.Hence, C5H13N is 2-aminopentane.Option B is correct.

The compound $C_{5} H_{13} N$ is optically active and reacts with HONO to give $C_{5} H_{11} O H$ . The compound is:

The correct option is B 2-aminopentane
Primary amine reacts with $H O N O$ to form alcohol.

Thus, $C_{5} H_{13} N$ is a primary amine.

$C_{5} H_{13} N$ is optically active compound.

Hence, $C_{5} H_{13} N$ is 2-aminopentane.

Option B is correct.