Question

The compound
$C_7{H}_8\stackrel{3C{l}_2/△}{\to }X\stackrel{B{r}_2/Fe}{\to }Y\stackrel{Zn/HCl}{\to }Z$
The compound $Z$ is :

• A. m-bromotoluene
• B. p-bromotoluene
• C. o-bromotoluene
• D. 2, 4, 6-trichlorotoluene

Answer 1

The correct option is A m-bromotoluene

In the first step, Toluene undergoes side-chain halogenation to give Benzotrichloride which is compound A. In the second step, benzotrichloride reacts with bromine in presence of Fe to give m-bromobenzotrichloride, which is compound B. And in the final step compound, B undergoes reduction with Zn and HCl to give the final product C as m-bromotoluene.