Question

The compound $C_8{H}_{18}$ forms single product on monohalogenation. The IUPAC name of $C_8{H}_{18}$ is :

• A. 2,2,3,3 - tetramethylbutane
• B. 2,3- dimethyl hexane
• C. n-octane
• D. 2,3,4 - trimethyl pentane

Answer 1

The correct option is A 2,2,3,3 - tetramethylbutane

Since $C_8{H}_{18}$ forms monohalogenated compound only, all the hydrogen atoms in it are equivalent.

Thus, it contains six equivalent methyl groups.

The IUPAC name of $C_8{H}_{18}$ is 2,2,3,3 - tetramethylbutane.

Option A is correct.