The compound $C H \equiv C C H_{2} C H_{2} C H = C H C H_{3}$ is subjected to oxidation with $C r O_{3} / C H_{3} C O O H$ . The products formed are:

C O_{2}, H O_{2} C C H_{2} C H_{2} C O_{2} H, C H_{3} C O_{2} H

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C O_{2}, H O_{2} C C H_{2} C H_{2} C H = C H C H_{3}

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C H \equiv C C H_{2} C H_{2} C O_{2} H, C H_{3} C O_{2} H

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H C O_{2} H, H O_{2} C C H_{2} C H_{2} C O_{2} H, C H_{3} C O_{2} H

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Solution

The correct option is C $C H \equiv C C H_{2} C H_{2} C O_{2} H, C H_{3} C O_{2} H$
$C r O_{3}$ in presence of $C H_{3} C O O H$ is a mild oxidising agent.

It will oxidise the alkene part and will not react with an alkyne. The reaction is shown below.

Option C is correct.

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