Question

The compound CuCl has zinc blende structure and the edge length of its unit cell is $500$ pm, its density (in g cm${}^{-3}$) is :

(Given that the atomic weight of $Cu$ is $63.5$ amu and of $Cl$ is $35.5$ amu.)

• A. $5.24$
• B. $1.14$
• C. $2.99$
• D. None of the above

Answer 1

The correct option is A $5.24$

density $=\frac{zM}{N_a\times (a\times {10}^{-10}{)}^3}$
density $=\frac{4\times 99}{6\times {10}^{23}\times (500\times {10}^{-10}{)}^3}$
density $=5.24{\text{gcm}}^{-3}$