Question

The compound having a tetrahedral geometry is :

• A. [Ni(CN${}_4$)]${}^{2-}$
• B. [Pd(CN${}_4$)]${}^{2-}$
• C. [PdCl${}_4$]${}^{2-}$
• D. [NiCl${}_4$]${}^{2-}$

Answer 1

The correct option is D [NiCl${}_4$]${}^{2-}$

$\left[Ni\right(Cl{)}_4{]}^{2-}$
The oxidation state of Ni is +2.
The atomic number of Nickel is 28.
Ni = $\left[Ar\right]3d^{8}4s^2$
$N{i}^{2+}=\left[Ar\right]3d^8$