The compound having molecular mass 63 u is

$[A t . m a s s o f N a = 23 u] [A t . m a s s o f C l = 35.5 u] [A t . m a s s o f O = 16 u] [A t . m a s s o f H = 1 u] [A t . m a s s o f N = 14 u]$

N a O H

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H N O_{3}

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H C l

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N a C l

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Solution

The correct option is B
$H N O_{3}$
Molecular mass of $H N O_{3} = (1 \times Atomic mass of H) + (1 \times Atomic mass of N) + (3 \times Atomic mass of O) = (1 \times 1) + (1 \times 14) + (3 \times 16) = 63 u$

Hence, the correct answer is option (b).

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Similar questions

N a, S

O

23 u, 32 u

16 u

{N a}_{2} O

A t o m i c m a s s o f N a = 23 u, O = 16 u

Calculate the molecular mass of ${H N O}_{3}$ ?

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