The compound having shortest S−O bond length is:
A
SO3F−
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
B
SO2−4
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
SOF4
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
SOCl2
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution
The correct option is ASO3F− Bond length is basically the average distance between nucleus of 2 bonded atoms in a molecule. The compound having shortest S−O bond length is :
SO3F−, as sulfur has 6 valance electrons and 5 of them are in bonding with oxygen and flourine is a strongly EN atom.
So, it attracts the electrons towards it strongly and reduces the bond length.