The compound having tetrahedral geometry is:

{[N i {(C N)}_{4}]}^{2 -}

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{[P d {(C N)}_{4}]}^{2 -}

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{[P d {C l}_{4}]}^{2 -}

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{[N i {C l}_{4}]}^{2 -}

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Solution

The correct option is C ${[N i {C l}_{4}]}^{2 -}$
$N i C l_{4}^{2 -}$ is tetrahedral because it has 4 bonds and no lone pairs of electrons, which means it has 4 regions of electron density.

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