The compound having the molecular formula C $_{4}$ H $_{10}$ does not show isomerism.

True

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False

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Solution

The correct option is B False
Molecule $C_{4} H_{10}$ shows isomerism.It has one isomer called iso butane in which one $- C H_{3}$ group gets attached to middle carbon if we write its original butane so called n-butane.Hence given statement is false.

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