The compound in which all carbon atoms use only $s p^{3}$ - hybrid orbitals for bond formation is?

C H_{3} C H O

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C H_{3} C O C H_{3}

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(C H_{3})_{3} C O H

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H C O O H

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Solution

The correct option is C $(C H_{3})_{3} C O H$
(A) Aldehyde, (B) acetone and (D) Formic acid do not have all the carbon $s p^{3}$ hybridized
However tertiary alcohol can have all the carbon $s p^{3}$ hybridized.
Option C is correct.

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