The compound in which the number of dπ−pπ bonds are equal to those present in ClO4− is:
A
XeF4
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B
XeO3
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C
XeO4
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D
XeF6
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Solution
The correct option is AXeO3 ClO−4 contains 3 dπ−pπ bonds in its molecule. XeO3 also contain 3 dπ−pπ bonds as shown in figure. Here formation of π bond takes place between d orbital electrons of Xe and p orbital electrons of oxygen.