The compound on reaction with $N a I O_{4}$ in the presence of $K M n O_{4}$ gives:

C H_{3} C O C H_{3}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

C H_{3} C O C H_{3} + C H_{3} C O O H

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

C H_{3} C O C H_{3} + C H_{3} C H O

No worries! We‘ve got your back. Try BYJU‘S free classes today!

C H_{3} C H O + C O_{2}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is C $C H_{3} C O C H_{3} + C H_{3} C O O H$
The given compound is isopentylene. When it reacts with $N a I O_{4}$ in presence of potassium permanganate it undergoes oxidation to form acetone and acetic acid respectively.

Suggest Corrections

Similar questions

The compound $C H_{3} | C H_{3} - C = C H - C H_{3}$ on reaction with $N a I O_{4}$ in the presence of $K M n O_{4}$ gives

(C H_{3})_{2} C = C H C H_{3}

K M n O_{4}

C H_{3} O H, C H_{3} C O O H, C H_{3} C H O, C H_{3} C O C H_{3}

C H_{3} C = C C H_{2} C H_{3} \frac{K M n O_{4} . K O H}{373 - 383 K}

C H_{3} C O C H_{3} Z a - H g - ----- \to c o n c . H C I

C H_{3} C O_{C} H_{3} (a) M g - H g d r y o t h e r - ----------------- \to (b) d i l . a c i d

C H_{3} C O_{2} H (a) B r_{2} + r e d P - --------- \to (b) H_{2} O

C H_{3} C H O H C N - -- \to

(H C O O H)_{2} C a d r y d i s t i l l a t i o n - --------- \to

Join BYJU'S Learning Program