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B
none of these
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C
a contingency
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D
a tautology
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Solution
The correct option is D a tautology p∧q)→(p∨q)⇔∼(p∧q)∨(p∨q)[∵(a→b)⇔(∼a∨b)]⇔(∼p∨∼q)∨(p∨q)[ByDemorgan′slaw]⇔(∼p∨p)∨(∼q∨q)[ByCommutativeandAssociativelaws]⇔T∨T⇔T