The compound(s) formed upon combustion of sodium metal in excess air is(are)

$N a_{2} O_{2}$

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$N a_{2} O$

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$N a O_{2}$

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$N a O H$

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Solution

The correct options are
A
$N a_{2} O_{2}$

B
$N a_{2} O$

Upon combustion,

$4 N a + O_{2} ⟶ 2 N a_{2} O$

And traces of peroxide is also formed.

$N a + O_{2} ⟶ N a_{2} O_{2}$

The superoxide and NaOH are not formed.

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