The compound(s) that exhibit(s) geometrical isomerism is (are):

[P t (e n) C l_{2}]

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[P t (e n)_{2}] C l_{2}

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[P t (e n)_{2} C l_{2}] C l_{2}

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[P t (N H_{3})_{2} C l_{2}]

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Solution

The correct options are
B $[P t (e n)_{2}] C l_{2}$
C $[P t (e n)_{2} C l_{2}] C l_{2}$
D $[P t (N H_{3})_{2} C l_{2}]$
Geometrical isomerism arises due to the difference in the geometrical arrangement of the ligands around the central ion. When the same kind of ligand occupies positions adjacent to each other called cis-isomer.

When identical ligands occupy positions opposite to each other called trans-isomer. It is very common in coordination complexes with a coordination number of 4 and 6.

The coordination numbers of options $A, B, C$ & $D$ are 3, 4, 6 & 4 respectively.

Hence, options $B, C$ & $D$ are correct.

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[C o (N H_{3})_{4} (H_{2} O)_{2}] C l_{2}, [N i (H_{2} O)_{6}] C l_{2}, [C o (H_{2} O)_{5} C l] C l, [P t (N H_{3})_{2} C l_{2}], [P t (e n) C l_{2}], [P t (e n)_{2} C l_{2}], [P b C l_{2} B r I], [C o (N H_{3}) 4 C l_{2}], [C o (e n)_{2} B r_{2}]

P t i n [P t {(e n)}_{2} {C l}_{2}] {C l}_{2}

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