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Question

The compound (SiH3)3N is expected to be:

A
Pyramidal and more basic than (CH3)3N
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B
Planar and less basic than (CH3)3N
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C
Pyramidal and less basic than (CH3)3N
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D
Planar and more basic than (CH3)3N
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Solution

The correct option is B Planar and less basic than (CH3)3N
In (SiH3)3N the lone pairs of nitrogen is delocalized to the empty orbitals of silicon due to which it is planar and less basic when compared to (CH3)3N.

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