Question

The compound $YB{a}_{2}C{u}_3{O}_7$, which shows super conductivity has copper in oxidation state of $\frac{7}{3}$.
Assume that the rare earth element ytterbium is in its usual $+3$ oxidation state.
If true enter 1, else enter 0.

• A. 1

Answer 1

The correct option is A 1
The compound $YB{a}_{2}C{u}_3{O}_7$, which shows super conductivity has copper in oxidation state is $\frac{7}{3}$.
Since the overall
charge on the complex is $0$, the sum of oxidation states of all elements in
it should be equal to $0$.
Assuming that the rare earth element ytterbium is in its usual $+3$ oxidation state,
$+3+2(+2)+3\left(\frac{7}{3}\right)+7(-2)=+3+4+7-14=0$
Thus, the given statement is true.