The compounds formed at the anode in the electrolysis of an aqueous solution of potassium acetate, are ____________ respectively.

C_{2} H_{6}

and

C O_{2}

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C_{2} H_{4}

and

C O_{2}

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C H_{4}

and

H_{2}

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C H_{4}

and

C O_{2}

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Solution

The correct option is A $C_{2} H_{6}$ and $C O_{2}$
$Kolbe's electrolysis:$

The Kolbe electrolysis or Kolbe reaction is an organic reaction named after Hermann Kolbe. The Kolbe reaction is formally a decarboxylative dimerisation of two carboxylic acids (or carboxylate ions) The overall general reaction is as shown in an image.

After electrolysis alkane is formed at anode along with the release of carbon-dioxide.
When potassium acetate $({C H_{3} C O O}^{-} K^{+})$ is used in electrolysis, carbon dioxide is released along with ethane $(H_{3} C - C H_{3})$
${C H_{3} C O O}^{-} ⟶ C H_{3} (r a d i c a l) + C O_{2}$

$C H_{3} (r a d i c a l) + C H_{3} (r a d i c a l) ⟶ C_{2} H_{6} (e t h a n e)$ is release at anode.
Option A is the correct answer.

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The volumes of gases $H_{2}, C H_{4}, C O_{2} a n d N H_{3}$ absorbed by 1 g of charcoal at 288 K are in the order:

Question 1
Calculate the molecular masses of $H_{2}, O_{2}, C l_{2}, C O_{2}, C H_{4}, C_{2} H_{6}, C_{2} H_{4}, N H_{3}, C H_{3} O H$ .

H_{2}, O_{2}, C l_{2}, C O_{2}, C H_{4}, C_{2} H_{6}, C_{2} H_{4}, N H_{3}, C H_{3} O H

C

C H_{4}, C_{2} H_{6}, C_{3} H_{8}, C_{2} H_{4}, C_{2} H_{2}, H_{2} C_{2} O_{4}

C O_{2}

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