Question

The compounds shown below have similar weights but significantly different boiling points. Match the compound with its boiling point. (Boiling points (${}^{o}C$) 28, 57, 100, 141).

• A. Methyl acetate=100, 2-butanol=141, 2-methyl butane=28, Propanoic acid=57
• B. Methyl acetate=57, 2-butanol=100, 2-methyl butane=28, Propanoic acid=141
• C. Methyl acetate=28, 2-butanol=100, 2-methyl butane=57, Propanoic acid=141
• D. Methyl acetate=141, 2-butanol=57, 2-methyl butane=28, Propanoic acid=100

Answer 1

The correct option is B Methyl acetate=57, 2-butanol=100, 2-methyl butane=28, Propanoic acid=141

Propanoic acid forms strongest H-bonds followed by butanol. 2-methyl butane, being non-polar, has lower boiling points than methylacetate .

So boiling points are, Methyl acetate=57, 2-butanol=100, 2-methyl butane=28, Propanoic acid=141