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Question

The compressibility factor for a real gas at high pressure is:


A
1+RTpb
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B
1
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C
1+pbRT
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D
1pbRT
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Solution

The correct option is B $$1+ \dfrac{pb}{RT}$$
Real gas equation is $$\displaystyle (P+ \frac{a}{V^2})(V-b)=RT$$
At high pressure, $$\displaystyle \frac{a}{V^2}$$ can be neglected.
$$PV-Pb=RT$$
$$\displaystyle \dfrac{PV}{RT}= 1+ \dfrac{Pb}{RT}$$..........(i)
$$\displaystyle Z= \dfrac{PV}{RT}$$.......(ii)
$$\displaystyle Z=1+\dfrac{Pb}{RT}$$

Chemistry

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