Question

# The compressibility factor for a real gas at high pressure is:

A
1+RTpb
B
1
C
1+pbRT
D
1pbRT

Solution

## The correct option is B $$1+ \dfrac{pb}{RT}$$Real gas equation is $$\displaystyle (P+ \frac{a}{V^2})(V-b)=RT$$At high pressure, $$\displaystyle \frac{a}{V^2}$$ can be neglected.$$PV-Pb=RT$$$$\displaystyle \dfrac{PV}{RT}= 1+ \dfrac{Pb}{RT}$$..........(i)$$\displaystyle Z= \dfrac{PV}{RT}$$.......(ii)$$\displaystyle Z=1+\dfrac{Pb}{RT}$$Chemistry

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