The compressibility factor for a real gas is expressed by, z=1+BPRT. The value of B at 500 K and 600 bar is 0.0169 L/mol. Find the molar volume of the gas
A
0.1 L
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B
9×10−5L
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C
8.62×10−2L/mol
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D
1.65 L
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Solution
The correct option is C8.62×10−2L/mol Given P= 600 bar, T=500 K, B = 0.016 L/mol
By substituting these values in the above equation, we get Z=1+0.0169×6000.083×500=1.244 Vm=ZRTP=1.244×0.083×500600
or Vm=8.6×10−2L