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Compressibility Factor

The compressi...

Question

The compressibility factor for $C O_{2}$ at 273 $K$ and 100 $a t m$ pressure is 0.2005. The volume occupied by 0.2 mole of $C O_{2}$ gas at 100 $a t m$ and 273 $K$ using real gas nature is $8.89 \times 10^{- x} l i t r e$ .
So, value of $x$ is.....

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Solution

For real gas $Z = \frac{P V}{n R T}$
$0.2005 = \frac{100 \times V}{0.2 \times 0.082 \times 273}$
$∴ V = 8.89 \times 10^{- 3} l i t r e$
so value of $x$ is 3.

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